[Dxspider-support] how to

[g3orh]

Hi Enric

               As Ian said to you (think it was Ian) the lat and long can be
decided by this :-

Degrees is either + or - . Plus for North of Equator / Minus for South of

The next bit is the minutes and only needs to be 2 or 3 decimal points.

IE lets assume 50 50 N

This would be +50 then 50/60 = .833  ( same calc method for long )
This is     50 divided by 60 where 50 is minutes of degrees.

My own lat/long is  +50 52 N and -3 47 W
This becomes           +50.866 for the north
and                         - 3.783 for the west

Hope this helps now

- Regards Colin   (73's)
- g3orh at ic24.net

----- Original Message -----
From: Enric EB6AOK <eb6aok at terra.es>
To: <dxspider-support at dxcluster.org>
Sent: Tuesday, July 31, 2001 9:04 PM
Subject: Re: [Dxspider-support] how to


> Hello to all
> and many thanks for your answers
> but it seems I was not clear enougth in my previous e-mail
> I like to know how to otain the correct dada for the
> folloing two lines of the DXVars.pm
> ----------------- origuinal lines
> $mylatitude = +52.68584579;
> $mylongiyude = +0.94518260:
> ----------------------
> I know my QTH is JM08PV allso know my lat long 38 53 15 N  1 17 30 E
> how I traslate to +x.xxxxxx ??